What are the solutions to the equation x^2+14=15x ?

The solutions to the equation x^2+14=15x are x=14,x=1

Find the zeros of x^2+14=15x

The zeros of x^2+14=15x are x=14,x=1

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x^{2} + 14 = 15 x

x = 14, x = 1

Solution steps

x^{2} + 14 = 15 x

Move

15 x

to the left side

x^{2} + 14 - 15 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 15 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 14 = 13

x_{1, 2} = \frac{- ( - 15 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 13}{2 \cdot 1}

x = \frac{- ( - 15 ) + 13}{2 \cdot 1} : 14

x = \frac{- ( - 15 ) - 13}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 14, x = 1

3 x^{2} + 60 x + 200 = 0

s, h (s) = - 16 s^{2} + 64 s + 190

2 = \frac{1}{2} \cdot 3 \cdot V^{2}

- 2 v^{2} - v + 12 = - 3 v^{2} + 6 v

4 x^{2} - 20 x + 1 = 0

What are the solutions to the equation x^2+14=15x ?
The solutions to the equation x^2+14=15x are x=14,x=1
Find the zeros of x^2+14=15x
The zeros of x^2+14=15x are x=14,x=1