What are the solutions to the equation completesquare t^2-8t-5=0 ?

The solutions to the equation completesquare t^2-8t-5=0 are t=sqrt(21)+4,t=-sqrt(21)+4

Find the zeros of completesquare t^2-8t-5=0

The zeros of completesquare t^2-8t-5=0 are t=sqrt(21)+4,t=-sqrt(21)+4

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t^{2} - 8 t - 5 = 0

t = 21 + 4, t = - 21 + 4

Decimal Notation

t = 8.58257 \dots, t = - 0.58257 \dots

Solution steps

t^{2} - 8 t - 5 = 0

Move

5

to the right side

t^{2} - 8 t = 5

Rewrite in the form

(x + a)^{2} = b

(t - 4)^{2} = 21

For

the solutions are

f (x) = a, - a

Solve

t - 4 = 21 : t = 21 + 4

Solve

t - 4 = - 21 : t = - 21 + 4

The solutions to the quadratic equation are:

t = 21 + 4, t = - 21 + 4

x^{2} + 6.5 x + 10 = 0

x^{2} + 4 x + 18 = 0

x^{2} - 10 x + 25 = 49

20 = - 2 x^{2} + 13 x

9 x^{2} + 3 = 111

What are the solutions to the equation completesquare t^2-8t-5=0 ?
The solutions to the equation completesquare t^2-8t-5=0 are t=sqrt(21)+4,t=-sqrt(21)+4
Find the zeros of completesquare t^2-8t-5=0
The zeros of completesquare t^2-8t-5=0 are t=sqrt(21)+4,t=-sqrt(21)+4