What are the solutions to the equation -2y+5+y^2=-6y+2y^2 ?

The solutions to the equation -2y+5+y^2=-6y+2y^2 are y=-1,y=5

Find the zeros of -2y+5+y^2=-6y+2y^2

The zeros of -2y+5+y^2=-6y+2y^2 are y=-1,y=5

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- 2 y + 5 + y^{2} = - 6 y + 2 y^{2}

y = - 1, y = 5

Solution steps

- 2 y + 5 + y^{2} = - 6 y + 2 y^{2}

Move

2 y^{2}

to the left side

- 2 y + 5 - y^{2} = - 6 y

Move

6 y

to the left side

- y^{2} + 4 y + 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 5 = 6

y_{1, 2} = \frac{- 4 \pm 6}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- 4 + 6}{2 ( - 1 )}, y_{2} = \frac{- 4 - 6}{2 ( - 1 )}

y = \frac{- 4 + 6}{2 ( - 1 )} : - 1

y = \frac{- 4 - 6}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

y = - 1, y = 5

5 x^{2} = - 10 - 27 x

3 x^{2} + 5 x = 1

x^{2} - 6 x - 11 = - 4

G (x) = 200 x - x^{2} - 4000

3 x^{2} + 7 = 55

What are the solutions to the equation -2y+5+y^2=-6y+2y^2 ?
The solutions to the equation -2y+5+y^2=-6y+2y^2 are y=-1,y=5
Find the zeros of -2y+5+y^2=-6y+2y^2
The zeros of -2y+5+y^2=-6y+2y^2 are y=-1,y=5