What are the solutions to the equation -4x^2+4x-3=0 ?

The solutions to the equation -4x^2+4x-3=0 are x= 1/2-i(sqrt(2))/2 ,x= 1/2+i(sqrt(2))/2

Find the zeros of -4x^2+4x-3=0

The zeros of -4x^2+4x-3=0 are x= 1/2-i(sqrt(2))/2 ,x= 1/2+i(sqrt(2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} + 4 x - 3 = 0

x = \frac{1}{2} - i \frac{2}{2}, x = \frac{1}{2} + i \frac{2}{2}

Solution steps

- 4 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

Simplify

4^{2} - 4 (- 4) (- 3) : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 ( - 4 )}, x_{2} = \frac{- 4 - 4 2 i}{2 ( - 4 )}

x = \frac{- 4 + 4 2 i}{2 ( - 4 )} : \frac{1}{2} - i \frac{2}{2}

x = \frac{- 4 - 4 2 i}{2 ( - 4 )} : \frac{1}{2} + i \frac{2}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{2}{2}, x = \frac{1}{2} + i \frac{2}{2}

20 x - 9 = x^{2}

2 x^{2} - 14 x - 16 = 0

r^{2} = - 624

9 x^{2} = 144

75 - 3 x^{2} = 0

What are the solutions to the equation -4x^2+4x-3=0 ?
The solutions to the equation -4x^2+4x-3=0 are x= 1/2-i(sqrt(2))/2 ,x= 1/2+i(sqrt(2))/2
Find the zeros of -4x^2+4x-3=0
The zeros of -4x^2+4x-3=0 are x= 1/2-i(sqrt(2))/2 ,x= 1/2+i(sqrt(2))/2