What are the solutions to the equation 1600-320x+12x^2=0 ?

The solutions to the equation 1600-320x+12x^2=0 are x=20,x= 20/3

Find the zeros of 1600-320x+12x^2=0

The zeros of 1600-320x+12x^2=0 are x=20,x= 20/3

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1600 - 320 x + 12 x^{2} = 0

x = 20, x = \frac{20}{3}

Decimal Notation

x = 20, x = 6.66666 \dots

Solution steps

1600 - 320 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 320 x + 1600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 320 ) \pm ( - 320 ) ^{2} - 4 \cdot 12 \cdot 1600}{2 \cdot 12}

(- 320)^{2} - 4 \cdot 12 \cdot 1600 = 160

x_{1, 2} = \frac{- ( - 320 ) \pm 160}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 320 ) + 160}{2 \cdot 12}, x_{2} = \frac{- ( - 320 ) - 160}{2 \cdot 12}

x = \frac{- ( - 320 ) + 160}{2 \cdot 12} : 20

x = \frac{- ( - 320 ) - 160}{2 \cdot 12} : \frac{20}{3}

The solutions to the quadratic equation are:

x = 20, x = \frac{20}{3}

1 = (1 - 2 (1) + 5) t^{2} + (2 (1) - 2 (1)) t + 1

x^{2} - 3 x + 1 = 0

0 = 3 x^{2} - 2 x - 1

(x + 9) (x - 7) = 0

2 x^{2} + 22 x + 36 = 0

What are the solutions to the equation 1600-320x+12x^2=0 ?
The solutions to the equation 1600-320x+12x^2=0 are x=20,x= 20/3
Find the zeros of 1600-320x+12x^2=0
The zeros of 1600-320x+12x^2=0 are x=20,x= 20/3