What are the solutions to the equation 36x^2+84x+49=0 ?

The solutions to the equation 36x^2+84x+49=0 are x=-7/6

Find the zeros of 36x^2+84x+49=0

The zeros of 36x^2+84x+49=0 are x=-7/6

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36 x^{2} + 84 x + 49 = 0

x = - \frac{7}{6}

Decimal Notation

x = - 1.16666 \dots

Solution steps

36 x^{2} + 84 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 84 \pm 8 4 ^{2} - 4 \cdot 36 \cdot 49}{2 \cdot 36}

8 4^{2} - 4 \cdot 36 \cdot 49 = 0

x_{1, 2} = \frac{- 84 \pm 0}{2 \cdot 36}

x = \frac{- 84}{2 \cdot 36}

\frac{- 84}{2 \cdot 36} = - \frac{7}{6}

x = - \frac{7}{6}

The solution to the quadratic equation is:

x = - \frac{7}{6}

x^{2} = 1 0^{2} + 6^{2}

x^{2} - 2 x - 5

(x + 8)^{2} = - 4

x^{2} - 2 x = 0

(x - 2) (2 x - 1) = 0

What are the solutions to the equation 36x^2+84x+49=0 ?
The solutions to the equation 36x^2+84x+49=0 are x=-7/6
Find the zeros of 36x^2+84x+49=0
The zeros of 36x^2+84x+49=0 are x=-7/6