What are the solutions to the equation 5x^2+3x-6=0 ?

The solutions to the equation 5x^2+3x-6=0 are x=(-3+sqrt(129))/(10),x=(-3-sqrt(129))/(10)

Find the zeros of 5x^2+3x-6=0

The zeros of 5x^2+3x-6=0 are x=(-3+sqrt(129))/(10),x=(-3-sqrt(129))/(10)

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5 x^{2} + 3 x - 6 = 0

x = \frac{- 3 + 129}{10}, x = \frac{- 3 - 129}{10}

Decimal Notation

x = 0.83578 \dots, x = - 1.43578 \dots

Solution steps

5 x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 6) = 129

x_{1, 2} = \frac{- 3 \pm 129}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 129}{2 \cdot 5}, x_{2} = \frac{- 3 - 129}{2 \cdot 5}

x = \frac{- 3 + 129}{2 \cdot 5} : \frac{- 3 + 129}{10}

x = \frac{- 3 - 129}{2 \cdot 5} : \frac{- 3 - 129}{10}

The solutions to the quadratic equation are:

x = \frac{- 3 + 129}{10}, x = \frac{- 3 - 129}{10}

16 - 6 x^{2} = 0

x, x^{2} - k x + 36 = 0

x^{2} - 4 x - 32 = 0

0.5 x^{2} - 2 x = - 2

x^{2} - 9 x - 90 = 0

What are the solutions to the equation 5x^2+3x-6=0 ?
The solutions to the equation 5x^2+3x-6=0 are x=(-3+sqrt(129))/(10),x=(-3-sqrt(129))/(10)
Find the zeros of 5x^2+3x-6=0
The zeros of 5x^2+3x-6=0 are x=(-3+sqrt(129))/(10),x=(-3-sqrt(129))/(10)