What are the solutions to the equation x^2-9x+13=0 ?

The solutions to the equation x^2-9x+13=0 are x=(9+sqrt(29))/2 ,x=(9-sqrt(29))/2

Find the zeros of x^2-9x+13=0

The zeros of x^2-9x+13=0 are x=(9+sqrt(29))/2 ,x=(9-sqrt(29))/2

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x^{2} - 9 x + 13 = 0

x = \frac{9 + 29}{2}, x = \frac{9 - 29}{2}

Decimal Notation

x = 7.19258 \dots, x = 1.80741 \dots

Solution steps

x^{2} - 9 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 13 = 29

x_{1, 2} = \frac{- ( - 9 ) \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 29}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 29}{2 \cdot 1}

x = \frac{- ( - 9 ) + 29}{2 \cdot 1} : \frac{9 + 29}{2}

x = \frac{- ( - 9 ) - 29}{2 \cdot 1} : \frac{9 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 29}{2}, x = \frac{9 - 29}{2}

x^{2} - 2 x - 5 = 0

x^{2} - 6 x - 16 = 0

24 x - 36 x^{2} = 0

x^{2} - x - 30 = 0

6 x (x - 2) = - 2 (x - 2)

What are the solutions to the equation x^2-9x+13=0 ?
The solutions to the equation x^2-9x+13=0 are x=(9+sqrt(29))/2 ,x=(9-sqrt(29))/2
Find the zeros of x^2-9x+13=0
The zeros of x^2-9x+13=0 are x=(9+sqrt(29))/2 ,x=(9-sqrt(29))/2