What are the solutions to the equation (5x+24)(4x+37)=0 ?

The solutions to the equation (5x+24)(4x+37)=0 are x=-24/5 ,x=-37/4

Find the zeros of (5x+24)(4x+37)=0

The zeros of (5x+24)(4x+37)=0 are x=-24/5 ,x=-37/4

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(5 x + 24) (4 x + 37) = 0

x = - \frac{24}{5}, x = - \frac{37}{4}

Decimal

x = - 4.8, x = - 9.25

Solution steps

(5 x + 24) (4 x + 37) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 24 = 0 or 4 x + 37 = 0

Solve

5 x + 24 = 0 : x = - \frac{24}{5}

Solve

4 x + 37 = 0 : x = - \frac{37}{4}

The solutions to the quadratic equation are:

x = - \frac{24}{5}, x = - \frac{37}{4}

(x + 5) (x + 1) = x - 1

x, f = I n (x^{2} + 7)

0 = x^{2} - x + 2

x, z^{3} + 3 z + y = x^{2} + 1

x^{2} - 4 x + 9

What are the solutions to the equation (5x+24)(4x+37)=0 ?
The solutions to the equation (5x+24)(4x+37)=0 are x=-24/5 ,x=-37/4
Find the zeros of (5x+24)(4x+37)=0
The zeros of (5x+24)(4x+37)=0 are x=-24/5 ,x=-37/4