What are the solutions to the equation n^2+n=0 ?

The solutions to the equation n^2+n=0 are n=0,n=-1

Find the zeros of n^2+n=0

The zeros of n^2+n=0 are n=0,n=-1

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n^{2} + n = 0

n = 0, n = - 1

Solution steps

n^{2} + n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

n_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 1 + 1}{2 \cdot 1}, n_{2} = \frac{- 1 - 1}{2 \cdot 1}

n = \frac{- 1 + 1}{2 \cdot 1} : 0

n = \frac{- 1 - 1}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

n = 0, n = - 1

20 x^{2} + 40 x = 0

x^{2} - 12 x + 35 = 195

x^{2} + \frac{13}{2} x + \frac{15}{2} = 0

9 x^{2} + 9 = 7 x^{2} + 27

9 t^{2} = 36 t - 1

What are the solutions to the equation n^2+n=0 ?
The solutions to the equation n^2+n=0 are n=0,n=-1
Find the zeros of n^2+n=0
The zeros of n^2+n=0 are n=0,n=-1