What are the solutions to the equation (x+1)^2=-4 ?

The solutions to the equation (x+1)^2=-4 are x=2i-1,x=-2i-1

Find the zeros of (x+1)^2=-4

The zeros of (x+1)^2=-4 are x=2i-1,x=-2i-1

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(x + 1)^{2} = - 4

x = 2 i - 1, x = - 2 i - 1

Solution steps

(x + 1)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 4 : x = 2 i - 1

Solve

x + 1 = - - 4 : x = - 2 i - 1

The solutions to the quadratic equation are:

x = 2 i - 1, x = - 2 i - 1

(x + 1)^{2} = 30

q, f D - 7 = q^{2}

x^{2} - 3 x + 2

x^{2} - 3 x - 4

5 x^{2} - 40 x + 50 = 0

What are the solutions to the equation (x+1)^2=-4 ?
The solutions to the equation (x+1)^2=-4 are x=2i-1,x=-2i-1
Find the zeros of (x+1)^2=-4
The zeros of (x+1)^2=-4 are x=2i-1,x=-2i-1