What are the solutions to the equation 9z^2+14z=8z-1 ?

The solutions to the equation 9z^2+14z=8z-1 are z=-1/3

Find the zeros of 9z^2+14z=8z-1

The zeros of 9z^2+14z=8z-1 are z=-1/3

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9 z^{2} + 14 z = 8 z - 1

z = - \frac{1}{3}

Decimal Notation

z = - 0.33333 \dots

Solution steps

9 z^{2} + 14 z = 8 z - 1

Move

1

to the left side

9 z^{2} + 14 z + 1 = 8 z

Move

8 z

to the left side

9 z^{2} + 6 z + 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

z_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

z = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

z = - \frac{1}{3}

The solution to the quadratic equation is:

z = - \frac{1}{3}

\frac{x}{2} + 2 x^{2} = - x (x - 1)

0 = - x^{2} + 4 x

x, x^{2} - y^{2} = c

4 x^{2} + 64 x + 467 = 15

50 = - 0.5 x^{2} + 40 x - 300

What are the solutions to the equation 9z^2+14z=8z-1 ?
The solutions to the equation 9z^2+14z=8z-1 are z=-1/3
Find the zeros of 9z^2+14z=8z-1
The zeros of 9z^2+14z=8z-1 are z=-1/3