What are the solutions to the equation 4x^2-15x=0 ?

The solutions to the equation 4x^2-15x=0 are x= 15/4 ,x=0

Find the zeros of 4x^2-15x=0

The zeros of 4x^2-15x=0 are x= 15/4 ,x=0

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4 x^{2} - 15 x = 0

x = \frac{15}{4}, x = 0

Solution steps

4 x^{2} - 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 15)^{2} - 4 \cdot 4 \cdot 0 = 15

x_{1, 2} = \frac{- ( - 15 ) \pm 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 15}{2 \cdot 4}, x_{2} = \frac{- ( - 15 ) - 15}{2 \cdot 4}

x = \frac{- ( - 15 ) + 15}{2 \cdot 4} : \frac{15}{4}

x = \frac{- ( - 15 ) - 15}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{15}{4}, x = 0

12 x^{2} - 112 x + 180 = 0

\frac{x ^{2}}{8} = \frac{1}{2}

x^{2} + 15 x - 2 = 0

(x + 8)^{2} = 4

7 x^{2} + 17 x + 6 = 0

What are the solutions to the equation 4x^2-15x=0 ?
The solutions to the equation 4x^2-15x=0 are x= 15/4 ,x=0
Find the zeros of 4x^2-15x=0
The zeros of 4x^2-15x=0 are x= 15/4 ,x=0