What are the solutions to the equation x^2+12x^2+48x+64=0 ?

The solutions to the equation x^2+12x^2+48x+64=0 are x=-24/13+i 16/13 ,x=-24/13-i 16/13

Find the zeros of x^2+12x^2+48x+64=0

The zeros of x^2+12x^2+48x+64=0 are x=-24/13+i 16/13 ,x=-24/13-i 16/13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 12 x^{2} + 48 x + 64 = 0

x = - \frac{24}{13} + i \frac{16}{13}, x = - \frac{24}{13} - i \frac{16}{13}

Solution steps

x^{2} + 12 x^{2} + 48 x + 64 = 0

Refine

13 x^{2} + 48 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 13 \cdot 64}{2 \cdot 13}

Simplify

4 8^{2} - 4 \cdot 13 \cdot 64 : 32 i

x_{1, 2} = \frac{- 48 \pm 32 i}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- 48 + 32 i}{2 \cdot 13}, x_{2} = \frac{- 48 - 32 i}{2 \cdot 13}

x = \frac{- 48 + 32 i}{2 \cdot 13} : - \frac{24}{13} + i \frac{16}{13}

x = \frac{- 48 - 32 i}{2 \cdot 13} : - \frac{24}{13} - i \frac{16}{13}

The solutions to the quadratic equation are:

x = - \frac{24}{13} + i \frac{16}{13}, x = - \frac{24}{13} - i \frac{16}{13}

x - 0 = 4

36 x^{2} + 84 x y + 49 y^{2}

3 < 2 x - 1 \leq 9

10 0^{\frac{3}{2}}

1 + \frac{5}{6}

What are the solutions to the equation x^2+12x^2+48x+64=0 ?
The solutions to the equation x^2+12x^2+48x+64=0 are x=-24/13+i 16/13 ,x=-24/13-i 16/13
Find the zeros of x^2+12x^2+48x+64=0
The zeros of x^2+12x^2+48x+64=0 are x=-24/13+i 16/13 ,x=-24/13-i 16/13