What are the solutions to the equation 9x^2-5x-7=0 ?

The solutions to the equation 9x^2-5x-7=0 are x=(5+sqrt(277))/(18),x=(5-sqrt(277))/(18)

Find the zeros of 9x^2-5x-7=0

The zeros of 9x^2-5x-7=0 are x=(5+sqrt(277))/(18),x=(5-sqrt(277))/(18)

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9 x^{2} - 5 x - 7 = 0

x = \frac{5 + 277}{18}, x = \frac{5 - 277}{18}

Solution steps

9 x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 9 ( - 7 )}{2 \cdot 9}

(- 5)^{2} - 4 \cdot 9 (- 7) = 277

x_{1, 2} = \frac{- ( - 5 ) \pm 277}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 277}{2 \cdot 9}, x_{2} = \frac{- ( - 5 ) - 277}{2 \cdot 9}

x = \frac{- ( - 5 ) + 277}{2 \cdot 9} : \frac{5 + 277}{18}

x = \frac{- ( - 5 ) - 277}{2 \cdot 9} : \frac{5 - 277}{18}

The solutions to the quadratic equation are:

x = \frac{5 + 277}{18}, x = \frac{5 - 277}{18}

(x + 8)^{2} - 4 = - 20

x^{2} - \frac{9}{16} = 0

1200 - 1.5 x^{2} = 200 + x^{2}

8 x^{2} - 200 = 0

(2 x - 1)^{2} - (x + 3)^{2} = 0

What are the solutions to the equation 9x^2-5x-7=0 ?
The solutions to the equation 9x^2-5x-7=0 are x=(5+sqrt(277))/(18),x=(5-sqrt(277))/(18)
Find the zeros of 9x^2-5x-7=0
The zeros of 9x^2-5x-7=0 are x=(5+sqrt(277))/(18),x=(5-sqrt(277))/(18)