What are the solutions to the equation -4x^2+5x-1=0 ?

The solutions to the equation -4x^2+5x-1=0 are x= 1/4 ,x=1

Find the zeros of -4x^2+5x-1=0

The zeros of -4x^2+5x-1=0 are x= 1/4 ,x=1

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- 4 x^{2} + 5 x - 1 = 0

x = \frac{1}{4}, x = 1

Solution steps

- 4 x^{2} + 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 4 ) ( - 1 )}{2 ( - 4 )}

5^{2} - 4 (- 4) (- 1) = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 ( - 4 )}, x_{2} = \frac{- 5 - 3}{2 ( - 4 )}

x = \frac{- 5 + 3}{2 ( - 4 )} : \frac{1}{4}

x = \frac{- 5 - 3}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 1

x^{2} - 16 x + 64 = 0

x^{2} + 10 x - 30 = 0

y, m = y^{2} - \frac{y ^{1}}{x ^{2}} - x^{1}

x, z^{2} + 4 y^{2} - 4 x^{2} = 0

3 r^{2} = 4 r - 1

What are the solutions to the equation -4x^2+5x-1=0 ?
The solutions to the equation -4x^2+5x-1=0 are x= 1/4 ,x=1
Find the zeros of -4x^2+5x-1=0
The zeros of -4x^2+5x-1=0 are x= 1/4 ,x=1