What are the solutions to the equation 4x^2-64=8x-4 ?

The solutions to the equation 4x^2-64=8x-4 are x=5,x=-3

Find the zeros of 4x^2-64=8x-4

The zeros of 4x^2-64=8x-4 are x=5,x=-3

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4 x^{2} - 64 = 8 x - 4

x = 5, x = - 3

Solution steps

4 x^{2} - 64 = 8 x - 4

Move

4

to the left side

4 x^{2} - 60 = 8 x

Move

8 x

to the left side

4 x^{2} - 60 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 8 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 60 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 60) = 32

x_{1, 2} = \frac{- ( - 8 ) \pm 32}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 32}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 32}{2 \cdot 4}

x = \frac{- ( - 8 ) + 32}{2 \cdot 4} : 5

x = \frac{- ( - 8 ) - 32}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

x^{2} - 8 x + 1

8 x^{2} - 14 x + 5 = 0

- 2 x^{2} - 12 x - 9 = 0

x^{2} + 22 x = 31

24 x^{2} - 14 x - 24 = 0

What are the solutions to the equation 4x^2-64=8x-4 ?
The solutions to the equation 4x^2-64=8x-4 are x=5,x=-3
Find the zeros of 4x^2-64=8x-4
The zeros of 4x^2-64=8x-4 are x=5,x=-3