What are the solutions to the equation 8x^2-20x=0 ?

The solutions to the equation 8x^2-20x=0 are x= 5/2 ,x=0

Find the zeros of 8x^2-20x=0

The zeros of 8x^2-20x=0 are x= 5/2 ,x=0

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8 x^{2} - 20 x = 0

x = \frac{5}{2}, x = 0

Solution steps

8 x^{2} - 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 20)^{2} - 4 \cdot 8 \cdot 0 = 20

x_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 8}, x_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 8}

x = \frac{- ( - 20 ) + 20}{2 \cdot 8} : \frac{5}{2}

x = \frac{- ( - 20 ) - 20}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 0

- \frac{23}{40} x^{2} + \frac{1}{2} x + 10 = 0

8 z^{2} - 9 z + 16 = 0

- 6 m^{2} = 48

(x - 1)^{2} = - 7

x^{2} + 2 x + 1 = 0

What are the solutions to the equation 8x^2-20x=0 ?
The solutions to the equation 8x^2-20x=0 are x= 5/2 ,x=0
Find the zeros of 8x^2-20x=0
The zeros of 8x^2-20x=0 are x= 5/2 ,x=0