What are the solutions to the equation -5x^2+95x+100=0 ?

The solutions to the equation -5x^2+95x+100=0 are x=-1,x=20

Find the zeros of -5x^2+95x+100=0

The zeros of -5x^2+95x+100=0 are x=-1,x=20

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- 5 x^{2} + 95 x + 100 = 0

x = - 1, x = 20

Solution steps

- 5 x^{2} + 95 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 95 \pm 9 5 ^{2} - 4 ( - 5 ) \cdot 100}{2 ( - 5 )}

9 5^{2} - 4 (- 5) \cdot 100 = 105

x_{1, 2} = \frac{- 95 \pm 105}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 95 + 105}{2 ( - 5 )}, x_{2} = \frac{- 95 - 105}{2 ( - 5 )}

x = \frac{- 95 + 105}{2 ( - 5 )} : - 1

x = \frac{- 95 - 105}{2 ( - 5 )} : 20

The solutions to the quadratic equation are:

x = - 1, x = 20

a x^{2} = 4 x - x^{2}

x^{2} - n^{2} x + 2 n = 0

4 x^{2} - 2 x + 5 = 0

(x - 2)^{2} + (x + 4)^{2} = 1

2 x^{2} + 8 x = 10

What are the solutions to the equation -5x^2+95x+100=0 ?
The solutions to the equation -5x^2+95x+100=0 are x=-1,x=20
Find the zeros of -5x^2+95x+100=0
The zeros of -5x^2+95x+100=0 are x=-1,x=20