What are the solutions to the equation x^2-16x+29=0 ?

The solutions to the equation x^2-16x+29=0 are x=8+sqrt(35),x=8-sqrt(35)

Find the zeros of x^2-16x+29=0

The zeros of x^2-16x+29=0 are x=8+sqrt(35),x=8-sqrt(35)

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x^{2} - 16 x + 29 = 0

x = 8 + 35, x = 8 - 35

Solution steps

x^{2} - 16 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 29 = 235

x_{1, 2} = \frac{- ( - 16 ) \pm 2 35}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 35}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 35}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 35}{2 \cdot 1} : 8 + 35

x = \frac{- ( - 16 ) - 2 35}{2 \cdot 1} : 8 - 35

The solutions to the quadratic equation are:

x = 8 + 35, x = 8 - 35

x^{2} + 5 x + c

x^{2} = - 30

x^{2} - 16 x + 27 = 0

a^{2} = 3

y, y^{2} = x

What are the solutions to the equation x^2-16x+29=0 ?
The solutions to the equation x^2-16x+29=0 are x=8+sqrt(35),x=8-sqrt(35)
Find the zeros of x^2-16x+29=0
The zeros of x^2-16x+29=0 are x=8+sqrt(35),x=8-sqrt(35)