What are the solutions to the equation r^2+3r=8 ?

The solutions to the equation r^2+3r=8 are r=(-3+sqrt(41))/2 ,r=(-3-sqrt(41))/2

Find the zeros of r^2+3r=8

The zeros of r^2+3r=8 are r=(-3+sqrt(41))/2 ,r=(-3-sqrt(41))/2

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r^{2} + 3 r = 8

r = \frac{- 3 + 41}{2}, r = \frac{- 3 - 41}{2}

Solution steps

r^{2} + 3 r = 8

Move

8

to the left side

r^{2} + 3 r - 8 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 8) = 41

r_{1, 2} = \frac{- 3 \pm 41}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 3 + 41}{2 \cdot 1}, r_{2} = \frac{- 3 - 41}{2 \cdot 1}

r = \frac{- 3 + 41}{2 \cdot 1} : \frac{- 3 + 41}{2}

r = \frac{- 3 - 41}{2 \cdot 1} : \frac{- 3 - 41}{2}

The solutions to the quadratic equation are:

r = \frac{- 3 + 41}{2}, r = \frac{- 3 - 41}{2}

x^{2} + 8 x + 16 = 0

2 x^{2} - 50 x = 0

3 r^{2} - 8 = 6

- 3 x^{2} - 2 x + 16 = 0

3 x^{2} - 12 x + 12 = (x - 3)

What are the solutions to the equation r^2+3r=8 ?
The solutions to the equation r^2+3r=8 are r=(-3+sqrt(41))/2 ,r=(-3-sqrt(41))/2
Find the zeros of r^2+3r=8
The zeros of r^2+3r=8 are r=(-3+sqrt(41))/2 ,r=(-3-sqrt(41))/2