What are the solutions to the equation s^2+4s+7=0 ?

The solutions to the equation s^2+4s+7=0 are s=-2+sqrt(3)i,s=-2-sqrt(3)i

Find the zeros of s^2+4s+7=0

The zeros of s^2+4s+7=0 are s=-2+sqrt(3)i,s=-2-sqrt(3)i

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s^{2} + 4 s + 7 = 0

s = - 2 + 3 i, s = - 2 - 3 i

Solution steps

s^{2} + 4 s + 7 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 7 : 23 i

s_{1, 2} = \frac{- 4 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 4 + 2 3 i}{2 \cdot 1}, s_{2} = \frac{- 4 - 2 3 i}{2 \cdot 1}

s = \frac{- 4 + 2 3 i}{2 \cdot 1} : - 2 + 3 i

s = \frac{- 4 - 2 3 i}{2 \cdot 1} : - 2 - 3 i

The solutions to the quadratic equation are:

s = - 2 + 3 i, s = - 2 - 3 i

2 x^{2} - 5 x = - 1

2 x (x - \frac{7}{2}) = 49

r, r^{2} + 1 = 0

6 x^{2} + 24 x - 30 = 0

- 3 x^{2} + 14 x - 14 = 0

What are the solutions to the equation s^2+4s+7=0 ?
The solutions to the equation s^2+4s+7=0 are s=-2+sqrt(3)i,s=-2-sqrt(3)i
Find the zeros of s^2+4s+7=0
The zeros of s^2+4s+7=0 are s=-2+sqrt(3)i,s=-2-sqrt(3)i