What are the solutions to the equation 0=-x^2-6x-7 ?

The solutions to the equation 0=-x^2-6x-7 are x=-3-sqrt(2),x=-3+sqrt(2)

Find the zeros of 0=-x^2-6x-7

The zeros of 0=-x^2-6x-7 are x=-3-sqrt(2),x=-3+sqrt(2)

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0 = - x^{2} - 6 x - 7

x = - 3 - 2, x = - 3 + 2

Solution steps

0 = - x^{2} - 6 x - 7

Switch sides

- x^{2} - 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) (- 7) = 22

x_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 2}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 2}{2 ( - 1 )} : - 3 - 2

x = \frac{- ( - 6 ) - 2 2}{2 ( - 1 )} : - 3 + 2

The solutions to the quadratic equation are:

x = - 3 - 2, x = - 3 + 2

- 10 + 3 x^{2} = 0

80 + y^{2} = 81

- x^{2} - 3 x - 4 = 0

20 - b^{2} = - 5

3 q (q - 3) = 12

What are the solutions to the equation 0=-x^2-6x-7 ?
The solutions to the equation 0=-x^2-6x-7 are x=-3-sqrt(2),x=-3+sqrt(2)
Find the zeros of 0=-x^2-6x-7
The zeros of 0=-x^2-6x-7 are x=-3-sqrt(2),x=-3+sqrt(2)