What are the solutions to the equation 2x^2=80 ?

The solutions to the equation 2x^2=80 are x=2sqrt(10),x=-2sqrt(10)

Find the zeros of 2x^2=80

The zeros of 2x^2=80 are x=2sqrt(10),x=-2sqrt(10)

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2 x^{2} = 80

x = 210, x = - 210

Solution steps

2 x^{2} = 80

Divide both sides by

2

x^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 40, x = - 40

40 = 210

- 40 = - 210

x = 210, x = - 210

7 x^{2} + 3 x - 4 = 0

15 x^{2} - 135 = 0

12 x^{2} + 2 x - 2 = 0

x^{2} + 13 x - 48 = 0

45 n^{2} + 10 n = 0

What are the solutions to the equation 2x^2=80 ?
The solutions to the equation 2x^2=80 are x=2sqrt(10),x=-2sqrt(10)
Find the zeros of 2x^2=80
The zeros of 2x^2=80 are x=2sqrt(10),x=-2sqrt(10)