What are the solutions to the equation 3x^2+6x-15=0 ?

The solutions to the equation 3x^2+6x-15=0 are x=-1+sqrt(6),x=-1-sqrt(6)

Find the zeros of 3x^2+6x-15=0

The zeros of 3x^2+6x-15=0 are x=-1+sqrt(6),x=-1-sqrt(6)

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3 x^{2} + 6 x - 15 = 0

x = - 1 + 6, x = - 1 - 6

Solution steps

3 x^{2} + 6 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 15) = 66

x_{1, 2} = \frac{- 6 \pm 6 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6 6}{2 \cdot 3}, x_{2} = \frac{- 6 - 6 6}{2 \cdot 3}

x = \frac{- 6 + 6 6}{2 \cdot 3} : - 1 + 6

x = \frac{- 6 - 6 6}{2 \cdot 3} : - 1 - 6

The solutions to the quadratic equation are:

x = - 1 + 6, x = - 1 - 6

x^{2} + 12 x + 8 = - 5

4 x^{2} + 22 x + 30 = 0

x, z = x^{2} y^{3}

s^{2} + 3 = 0

12 x^{2} + 24 x - 96 = 0

What are the solutions to the equation 3x^2+6x-15=0 ?
The solutions to the equation 3x^2+6x-15=0 are x=-1+sqrt(6),x=-1-sqrt(6)
Find the zeros of 3x^2+6x-15=0
The zeros of 3x^2+6x-15=0 are x=-1+sqrt(6),x=-1-sqrt(6)