What are the solutions to the equation 9x^2-3x=2 ?

The solutions to the equation 9x^2-3x=2 are x= 2/3 ,x=-1/3

Find the zeros of 9x^2-3x=2

The zeros of 9x^2-3x=2 are x= 2/3 ,x=-1/3

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9 x^{2} - 3 x = 2

x = \frac{2}{3}, x = - \frac{1}{3}

Solution steps

9 x^{2} - 3 x = 2

Move

2

to the left side

9 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

(- 3)^{2} - 4 \cdot 9 (- 2) = 9

x_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 9}

x = \frac{- ( - 3 ) + 9}{2 \cdot 9} : \frac{2}{3}

x = \frac{- ( - 3 ) - 9}{2 \cdot 9} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{1}{3}

9 x^{2} - 20 x = 0

(5 x - 12)^{2} - 1 = 8

x^{2} - 12 x - 3 = 0

x^{2} - 3 x = - 1

x^{2} - 3 x = 54

What are the solutions to the equation 9x^2-3x=2 ?
The solutions to the equation 9x^2-3x=2 are x= 2/3 ,x=-1/3
Find the zeros of 9x^2-3x=2
The zeros of 9x^2-3x=2 are x= 2/3 ,x=-1/3