What are the solutions to the equation 4x^2+25=-20x ?

The solutions to the equation 4x^2+25=-20x are x=-5/2

Find the zeros of 4x^2+25=-20x

The zeros of 4x^2+25=-20x are x=-5/2

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4 x^{2} + 25 = - 20 x

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

4 x^{2} + 25 = - 20 x

Move

20 x

to the left side

4 x^{2} + 25 + 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

x = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

x = - \frac{5}{2}

The solution to the quadratic equation is:

x = - \frac{5}{2}

4 x^{2} - x - 8 = 0

5 x^{2} - 100 x + 465 = 0

- 3 w^{2} - 78 = 138

v^{2} = - 9

x^{2} - 3 x - 27 = 0

What are the solutions to the equation 4x^2+25=-20x ?
The solutions to the equation 4x^2+25=-20x are x=-5/2
Find the zeros of 4x^2+25=-20x
The zeros of 4x^2+25=-20x are x=-5/2