What are the solutions to the equation x^2+20x+20=0 ?

The solutions to the equation x^2+20x+20=0 are x=2(2sqrt(5)-5),x=-2(5+2sqrt(5))

Find the zeros of x^2+20x+20=0

The zeros of x^2+20x+20=0 are x=2(2sqrt(5)-5),x=-2(5+2sqrt(5))

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x^{2} + 20 x + 20 = 0

x = 2 (25 - 5), x = - 2 (5 + 25)

Solution steps

x^{2} + 20 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 20 = 85

x_{1, 2} = \frac{- 20 \pm 8 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 8 5}{2 \cdot 1}, x_{2} = \frac{- 20 - 8 5}{2 \cdot 1}

x = \frac{- 20 + 8 5}{2 \cdot 1} : 2 (25 - 5)

x = \frac{- 20 - 8 5}{2 \cdot 1} : - 2 (5 + 25)

The solutions to the quadratic equation are:

x = 2 (25 - 5), x = - 2 (5 + 25)

2 x^{2} + 1 = 3 x

2 x^{2} - 24 x + 144 = 0

- 12 w^{2} = 7 + 6 w

96 = 80 t - 16 t^{2}

x^{2} + 4 x + 4 = 0

What are the solutions to the equation x^2+20x+20=0 ?
The solutions to the equation x^2+20x+20=0 are x=2(2sqrt(5)-5),x=-2(5+2sqrt(5))
Find the zeros of x^2+20x+20=0
The zeros of x^2+20x+20=0 are x=2(2sqrt(5)-5),x=-2(5+2sqrt(5))