What are the solutions to the equation solvefor x,x^2-5x+4=0 ?

The solutions to the equation solvefor x,x^2-5x+4=0 are x=4,x=1

Find the zeros of solvefor x,x^2-5x+4=0

The zeros of solvefor x,x^2-5x+4=0 are x=4,x=1

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x, x^{2} - 5 x + 4 = 0

x = 4, x = 1

Solution steps

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

0.75 x^{2} - 1.7 x + 0.5 = 0

14 x^{2} = 3, 5 x = 0

3 x^{2} - 3 x - 8 = 0

5 x^{2} - 2 x + 6 = 0

x^{2} - 5 x + 11 = 0

What are the solutions to the equation solvefor x,x^2-5x+4=0 ?
The solutions to the equation solvefor x,x^2-5x+4=0 are x=4,x=1
Find the zeros of solvefor x,x^2-5x+4=0
The zeros of solvefor x,x^2-5x+4=0 are x=4,x=1