What are the solutions to the equation 10x^2+5=1 ?

The solutions to the equation 10x^2+5=1 are x=sqrt(2/5)i,x=-sqrt(2/5)i

Find the zeros of 10x^2+5=1

The zeros of 10x^2+5=1 are x=sqrt(2/5)i,x=-sqrt(2/5)i

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10 x^{2} + 5 = 1

x = \frac{2}{5} i, x = - \frac{2}{5} i

Solution steps

10 x^{2} + 5 = 1

Move

5

to the right side

10 x^{2} = - 4

Divide both sides by

10

x^{2} = - \frac{2}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2}{5}, x = - - \frac{2}{5}

- \frac{2}{5} = \frac{2}{5} i

- - \frac{2}{5} = - \frac{2}{5} i

x = \frac{2}{5} i, x = - \frac{2}{5} i

25 = x^{2} + 14 x + 49

2 x^{2} - 3 x = - 2

115 + 12.25 t - 4.9 t^{2}

(m - 3) x^{2} + (m - 7) x + 2 = 0

2 x^{2} - 3 x = - 5

What are the solutions to the equation 10x^2+5=1 ?
The solutions to the equation 10x^2+5=1 are x=sqrt(2/5)i,x=-sqrt(2/5)i
Find the zeros of 10x^2+5=1
The zeros of 10x^2+5=1 are x=sqrt(2/5)i,x=-sqrt(2/5)i