What are the solutions to the equation 2x^2-12x=0 ?

The solutions to the equation 2x^2-12x=0 are x=6,x=0

Find the zeros of 2x^2-12x=0

The zeros of 2x^2-12x=0 are x=6,x=0

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2 x^{2} - 12 x = 0

x = 6, x = 0

Solution steps

2 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 2}

x = \frac{- ( - 12 ) + 12}{2 \cdot 2} : 6

x = \frac{- ( - 12 ) - 12}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 6, x = 0

\frac{3}{10} + \frac{1}{4}

3 (3 v - 4) = 51

3 + \frac{1}{6}

∣ 6 - 7 x ∣ = 11

\frac{12 x y}{7 x ^{4}} \cdot \frac{7 x ^{5} y ^{2}}{4 y}

What are the solutions to the equation 2x^2-12x=0 ?
The solutions to the equation 2x^2-12x=0 are x=6,x=0
Find the zeros of 2x^2-12x=0
The zeros of 2x^2-12x=0 are x=6,x=0