What are the solutions to the equation solvefor x,x^2+y^2+4=0 ?

The solutions to the equation solvefor x,x^2+y^2+4=0 are x=sqrt(-y^2-4),x=-sqrt(-y^2-4)

Find the zeros of solvefor x,x^2+y^2+4=0

The zeros of solvefor x,x^2+y^2+4=0 are x=sqrt(-y^2-4),x=-sqrt(-y^2-4)

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solve for

x, x^{2} + y^{2} + 4 = 0

x = - y^{2} - 4, x = - - y^{2} - 4

Solution steps

x^{2} + y^{2} + 4 = 0

Move

y^{2}

to the right side

x^{2} + 4 = - y^{2}

Move

4

to the right side

x^{2} = - y^{2} - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - y^{2} - 4, x = - - y^{2} - 4

3 (x - 2)^{2} = 0

x, x^{2} + y^{2} + 9 = 0

(0.75 \cdot 1 0^{4}) x = (- 3000 x + 15 - 1)^{2}

4 v^{2} = - 12 v - 5

x^{2} + 4 x - 12 = 0

What are the solutions to the equation solvefor x,x^2+y^2+4=0 ?
The solutions to the equation solvefor x,x^2+y^2+4=0 are x=sqrt(-y^2-4),x=-sqrt(-y^2-4)
Find the zeros of solvefor x,x^2+y^2+4=0
The zeros of solvefor x,x^2+y^2+4=0 are x=sqrt(-y^2-4),x=-sqrt(-y^2-4)