What are the solutions to the equation 15x^2+1.5x+1=0 ?

The solutions to the equation 15x^2+1.5x+1=0 are x=-1/20+i(sqrt(231))/(60),x=-1/20-i(sqrt(231))/(60)

Find the zeros of 15x^2+1.5x+1=0

The zeros of 15x^2+1.5x+1=0 are x=-1/20+i(sqrt(231))/(60),x=-1/20-i(sqrt(231))/(60)

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15 x^{2} + 1.5 x + 1 = 0

x = - \frac{1}{20} + i \frac{231}{60}, x = - \frac{1}{20} - i \frac{231}{60}

Solution steps

15 x^{2} + 1.5 x + 1 = 0

Multiply both sides by

10

150 x^{2} + 15 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 150 \cdot 10}{2 \cdot 150}

Simplify

1 5^{2} - 4 \cdot 150 \cdot 10 : 5231 i

x_{1, 2} = \frac{- 15 \pm 5 231 i}{2 \cdot 150}

Separate the solutions

x_{1} = \frac{- 15 + 5 231 i}{2 \cdot 150}, x_{2} = \frac{- 15 - 5 231 i}{2 \cdot 150}

x = \frac{- 15 + 5 231 i}{2 \cdot 150} : - \frac{1}{20} + i \frac{231}{60}

x = \frac{- 15 - 5 231 i}{2 \cdot 150} : - \frac{1}{20} - i \frac{231}{60}

The solutions to the quadratic equation are:

x = - \frac{1}{20} + i \frac{231}{60}, x = - \frac{1}{20} - i \frac{231}{60}

- x^{2} - 2 x + 48 = 3 x + 12

9 x^{2} - 3 = 0

9 (x^{2} - 11) - 8 = 14

4 x^{2} - 8 = x

\frac{x ^{2}}{3} - \frac{x}{5} = 0

What are the solutions to the equation 15x^2+1.5x+1=0 ?
The solutions to the equation 15x^2+1.5x+1=0 are x=-1/20+i(sqrt(231))/(60),x=-1/20-i(sqrt(231))/(60)
Find the zeros of 15x^2+1.5x+1=0
The zeros of 15x^2+1.5x+1=0 are x=-1/20+i(sqrt(231))/(60),x=-1/20-i(sqrt(231))/(60)