What are the solutions to the equation m^2+4m+40=0 ?

The solutions to the equation m^2+4m+40=0 are m=-2+6i,m=-2-6i

Find the zeros of m^2+4m+40=0

The zeros of m^2+4m+40=0 are m=-2+6i,m=-2-6i

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m^{2} + 4 m + 40 = 0

m = - 2 + 6 i, m = - 2 - 6 i

Solution steps

m^{2} + 4 m + 40 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 40 : 12 i

m_{1, 2} = \frac{- 4 \pm 12 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 12 i}{2 \cdot 1}, m_{2} = \frac{- 4 - 12 i}{2 \cdot 1}

m = \frac{- 4 + 12 i}{2 \cdot 1} : - 2 + 6 i

m = \frac{- 4 - 12 i}{2 \cdot 1} : - 2 - 6 i

The solutions to the quadratic equation are:

m = - 2 + 6 i, m = - 2 - 6 i

200 x - \frac{1}{4} x^{2} = 52 x + \frac{3}{4} x^{2} + 2112

3 x^{2} - 3 = 3 x

5 x^{2} + 50 x + 45 = 0

5 x^{2} = 900

5 x^{2} = 3 x^{2} + 24

What are the solutions to the equation m^2+4m+40=0 ?
The solutions to the equation m^2+4m+40=0 are m=-2+6i,m=-2-6i
Find the zeros of m^2+4m+40=0
The zeros of m^2+4m+40=0 are m=-2+6i,m=-2-6i