What are the solutions to the equation -2x^2-15x-4=-3x^2 ?

The solutions to the equation -2x^2-15x-4=-3x^2 are x=(15+sqrt(241))/2 ,x=(15-sqrt(241))/2

Find the zeros of -2x^2-15x-4=-3x^2

The zeros of -2x^2-15x-4=-3x^2 are x=(15+sqrt(241))/2 ,x=(15-sqrt(241))/2

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- 2 x^{2} - 15 x - 4 = - 3 x^{2}

x = \frac{15 + 241}{2}, x = \frac{15 - 241}{2}

Decimal Notation

x = 15.26208 \dots, x = - 0.26208 \dots

Solution steps

- 2 x^{2} - 15 x - 4 = - 3 x^{2}

Move

3 x^{2}

to the left side

x^{2} - 15 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot (- 4) = 241

x_{1, 2} = \frac{- ( - 15 ) \pm 241}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 241}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 241}{2 \cdot 1}

x = \frac{- ( - 15 ) + 241}{2 \cdot 1} : \frac{15 + 241}{2}

x = \frac{- ( - 15 ) - 241}{2 \cdot 1} : \frac{15 - 241}{2}

The solutions to the quadratic equation are:

x = \frac{15 + 241}{2}, x = \frac{15 - 241}{2}

- 120 - 26 x = x^{2}

2 x^{2} - 22 x + 60 = 0

3 x^{2} - 23 x + 14 = 0

72 x^{2} - 12 x - 24 = 0

x^{2} - 2 x - 100 = 0

What are the solutions to the equation -2x^2-15x-4=-3x^2 ?
The solutions to the equation -2x^2-15x-4=-3x^2 are x=(15+sqrt(241))/2 ,x=(15-sqrt(241))/2
Find the zeros of -2x^2-15x-4=-3x^2
The zeros of -2x^2-15x-4=-3x^2 are x=(15+sqrt(241))/2 ,x=(15-sqrt(241))/2