What are the solutions to the equation 15x^2+34x-77=0 ?

The solutions to the equation 15x^2+34x-77=0 are x= 7/5 ,x=-11/3

Find the zeros of 15x^2+34x-77=0

The zeros of 15x^2+34x-77=0 are x= 7/5 ,x=-11/3

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15 x^{2} + 34 x - 77 = 0

x = \frac{7}{5}, x = - \frac{11}{3}

Solution steps

15 x^{2} + 34 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 34 \pm 3 4 ^{2} - 4 \cdot 15 ( - 77 )}{2 \cdot 15}

3 4^{2} - 4 \cdot 15 (- 77) = 76

x_{1, 2} = \frac{- 34 \pm 76}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 34 + 76}{2 \cdot 15}, x_{2} = \frac{- 34 - 76}{2 \cdot 15}

x = \frac{- 34 + 76}{2 \cdot 15} : \frac{7}{5}

x = \frac{- 34 - 76}{2 \cdot 15} : - \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{7}{5}, x = - \frac{11}{3}

3 x^{1} + 6 x^{2} = 9, - 2 x^{1} + 3 x^{2} = 4

\frac{x ^{2} - x}{2} - \frac{( x - 4 ) ^{2}}{3} = 0

- 0.45 x^{2} + 5.52 x - 13.7 = 0

x, z = 4 (x - y) - x^{2} - y^{2}

20 x^{2} - 27 x - 14 = 0

What are the solutions to the equation 15x^2+34x-77=0 ?
The solutions to the equation 15x^2+34x-77=0 are x= 7/5 ,x=-11/3
Find the zeros of 15x^2+34x-77=0
The zeros of 15x^2+34x-77=0 are x= 7/5 ,x=-11/3