What are the solutions to the equation -3x^2+18x=-30 ?

The solutions to the equation -3x^2+18x=-30 are x=3-sqrt(19),x=3+sqrt(19)

Find the zeros of -3x^2+18x=-30

The zeros of -3x^2+18x=-30 are x=3-sqrt(19),x=3+sqrt(19)

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- 3 x^{2} + 18 x = - 30

x = 3 - 19, x = 3 + 19

Solution steps

- 3 x^{2} + 18 x = - 30

Move

30

to the left side

- 3 x^{2} + 18 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 3 ) \cdot 30}{2 ( - 3 )}

1 8^{2} - 4 (- 3) \cdot 30 = 619

x_{1, 2} = \frac{- 18 \pm 6 19}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 18 + 6 19}{2 ( - 3 )}, x_{2} = \frac{- 18 - 6 19}{2 ( - 3 )}

x = \frac{- 18 + 6 19}{2 ( - 3 )} : 3 - 19

x = \frac{- 18 - 6 19}{2 ( - 3 )} : 3 + 19

The solutions to the quadratic equation are:

x = 3 - 19, x = 3 + 19

6 - x^{2} = 0

x^{2} + 8 x + 15

x^{2} + m x + n = 0

10 - 7 s^{2} = 1

28 = - t^{2} + 3 t + 27

What are the solutions to the equation -3x^2+18x=-30 ?
The solutions to the equation -3x^2+18x=-30 are x=3-sqrt(19),x=3+sqrt(19)
Find the zeros of -3x^2+18x=-30
The zeros of -3x^2+18x=-30 are x=3-sqrt(19),x=3+sqrt(19)