What are the solutions to the equation 5=(x-3)^2 ?

The solutions to the equation 5=(x-3)^2 are x=sqrt(5)+3,x=-sqrt(5)+3

Find the zeros of 5=(x-3)^2

The zeros of 5=(x-3)^2 are x=sqrt(5)+3,x=-sqrt(5)+3

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5 = (x - 3)^{2}

x = 5 + 3, x = - 5 + 3

Decimal Notation

x = 5.23606 \dots, x = 0.76393 \dots

Solution steps

5 = (x - 3)^{2}

Switch sides

(x - 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 5 : x = 5 + 3

Solve

x - 3 = - 5 : x = - 5 + 3

The solutions to the quadratic equation are:

x = 5 + 3, x = - 5 + 3

x^{2} = a^{2} + a^{2}

x^{2} + 3^{2} = 8^{2}

x^{2} + 13 x + 15 = 0

x^{2} - 24 = 2 x

- 2 x^{2} - 6 = x

What are the solutions to the equation 5=(x-3)^2 ?
The solutions to the equation 5=(x-3)^2 are x=sqrt(5)+3,x=-sqrt(5)+3
Find the zeros of 5=(x-3)^2
The zeros of 5=(x-3)^2 are x=sqrt(5)+3,x=-sqrt(5)+3