What are the solutions to the equation 1.2x^2+5x=3 ?

The solutions to the equation 1.2x^2+5x=3 are x=(-25+sqrt(985))/(12),x=-(25+sqrt(985))/(12)

Find the zeros of 1.2x^2+5x=3

The zeros of 1.2x^2+5x=3 are x=(-25+sqrt(985))/(12),x=-(25+sqrt(985))/(12)

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1.2 x^{2} + 5 x = 3

x = \frac{- 25 + 985}{12}, x = - \frac{25 + 985}{12}

Solution steps

1.2 x^{2} + 5 x = 3

Multiply both sides by

10

12 x^{2} + 50 x = 30

Move

30

to the left side

12 x^{2} + 50 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 12 ( - 30 )}{2 \cdot 12}

5 0^{2} - 4 \cdot 12 (- 30) = 2985

x_{1, 2} = \frac{- 50 \pm 2 985}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 50 + 2 985}{2 \cdot 12}, x_{2} = \frac{- 50 - 2 985}{2 \cdot 12}

x = \frac{- 50 + 2 985}{2 \cdot 12} : \frac{- 25 + 985}{12}

x = \frac{- 50 - 2 985}{2 \cdot 12} : - \frac{25 + 985}{12}

The solutions to the quadratic equation are:

x = \frac{- 25 + 985}{12}, x = - \frac{25 + 985}{12}

(8 - d)^{2} + 81 = 100

(x + 1)^{2} = 2 x^{2}

0 = - x^{2}

7 x^{2} + b x + c = 0

5 v^{2} + 30 v = 0

What are the solutions to the equation 1.2x^2+5x=3 ?
The solutions to the equation 1.2x^2+5x=3 are x=(-25+sqrt(985))/(12),x=-(25+sqrt(985))/(12)
Find the zeros of 1.2x^2+5x=3
The zeros of 1.2x^2+5x=3 are x=(-25+sqrt(985))/(12),x=-(25+sqrt(985))/(12)