What are the solutions to the equation 2x^2+7x+8=0 ?

The solutions to the equation 2x^2+7x+8=0 are x=-7/4+i(sqrt(15))/4 ,x=-7/4-i(sqrt(15))/4

Find the zeros of 2x^2+7x+8=0

The zeros of 2x^2+7x+8=0 are x=-7/4+i(sqrt(15))/4 ,x=-7/4-i(sqrt(15))/4

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2 x^{2} + 7 x + 8 = 0

x = - \frac{7}{4} + i \frac{15}{4}, x = - \frac{7}{4} - i \frac{15}{4}

Solution steps

2 x^{2} + 7 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

7^{2} - 4 \cdot 2 \cdot 8 : 15 i

x_{1, 2} = \frac{- 7 \pm 15 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 15 i}{2 \cdot 2}, x_{2} = \frac{- 7 - 15 i}{2 \cdot 2}

x = \frac{- 7 + 15 i}{2 \cdot 2} : - \frac{7}{4} + i \frac{15}{4}

x = \frac{- 7 - 15 i}{2 \cdot 2} : - \frac{7}{4} - i \frac{15}{4}

The solutions to the quadratic equation are:

x = - \frac{7}{4} + i \frac{15}{4}, x = - \frac{7}{4} - i \frac{15}{4}

5 d (3 d + 2) = 0

9 - x^{2} = x + 1

x^{2} - x = 0

b x^{2} + 5 = 6

3 0^{2} + 4 0^{2} = c^{2}

What are the solutions to the equation 2x^2+7x+8=0 ?
The solutions to the equation 2x^2+7x+8=0 are x=-7/4+i(sqrt(15))/4 ,x=-7/4-i(sqrt(15))/4
Find the zeros of 2x^2+7x+8=0
The zeros of 2x^2+7x+8=0 are x=-7/4+i(sqrt(15))/4 ,x=-7/4-i(sqrt(15))/4