What are the solutions to the equation x^2-10x=6 ?

The solutions to the equation x^2-10x=6 are x=5+sqrt(31),x=5-sqrt(31)

Find the zeros of x^2-10x=6

The zeros of x^2-10x=6 are x=5+sqrt(31),x=5-sqrt(31)

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x^{2} - 10 x = 6

x = 5 + 31, x = 5 - 31

Solution steps

x^{2} - 10 x = 6

Move

6

to the left side

x^{2} - 10 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 6) = 231

x_{1, 2} = \frac{- ( - 10 ) \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 31}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 31}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 31}{2 \cdot 1} : 5 + 31

x = \frac{- ( - 10 ) - 2 31}{2 \cdot 1} : 5 - 31

The solutions to the quadratic equation are:

x = 5 + 31, x = 5 - 31

2 m^{2} + 2 m - 24 = 0

- x^{2} = 5

x^{2} + \frac{2}{3} x + 1

x^{2} - 5 x - 36 = 0

x^{2} + 10 x + 21 = 0

What are the solutions to the equation x^2-10x=6 ?
The solutions to the equation x^2-10x=6 are x=5+sqrt(31),x=5-sqrt(31)
Find the zeros of x^2-10x=6
The zeros of x^2-10x=6 are x=5+sqrt(31),x=5-sqrt(31)