What are the solutions to the equation 3x^2=5+8x ?

The solutions to the equation 3x^2=5+8x are x=(4+sqrt(31))/3 ,x=(4-sqrt(31))/3

Find the zeros of 3x^2=5+8x

The zeros of 3x^2=5+8x are x=(4+sqrt(31))/3 ,x=(4-sqrt(31))/3

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3 x^{2} = 5 + 8 x

x = \frac{4 + 31}{3}, x = \frac{4 - 31}{3}

Decimal Notation

x = 3.18925 \dots, x = - 0.52258 \dots

Solution steps

3 x^{2} = 5 + 8 x

Move

8 x

to the left side

3 x^{2} - 8 x = 5

Move

5

to the left side

3 x^{2} - 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 5) = 231

x_{1, 2} = \frac{- ( - 8 ) \pm 2 31}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 31}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2 31}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2 31}{2 \cdot 3} : \frac{4 + 31}{3}

x = \frac{- ( - 8 ) - 2 31}{2 \cdot 3} : \frac{4 - 31}{3}

The solutions to the quadratic equation are:

x = \frac{4 + 31}{3}, x = \frac{4 - 31}{3}

(x + 7)^{2} = 16

9 x^{2} + 25 = - 30 x

y, x^{2} + 4 y^{2} = 4

x^{2} + 2 x + x = 0

(x) = a x^{2} + b x + c

What are the solutions to the equation 3x^2=5+8x ?
The solutions to the equation 3x^2=5+8x are x=(4+sqrt(31))/3 ,x=(4-sqrt(31))/3
Find the zeros of 3x^2=5+8x
The zeros of 3x^2=5+8x are x=(4+sqrt(31))/3 ,x=(4-sqrt(31))/3