What are the solutions to the equation (x^2)/(25)+(x^2)/(16)=1 ?

The solutions to the equation (x^2)/(25)+(x^2)/(16)=1 are x=(20)/(sqrt(41)),x=-(20)/(sqrt(41))

Find the zeros of (x^2)/(25)+(x^2)/(16)=1

The zeros of (x^2)/(25)+(x^2)/(16)=1 are x=(20)/(sqrt(41)),x=-(20)/(sqrt(41))

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\frac{x ^{2}}{25} + \frac{x ^{2}}{16} = 1

x = \frac{20}{41}, x = - \frac{20}{41}

Decimal Notation

x = 3.12347 \dots, x = - 3.12347 \dots

Solution steps

\frac{x ^{2}}{25} + \frac{x ^{2}}{16} = 1

Multiply by LCM

41 x^{2} = 400

Divide both sides by

41

x^{2} = \frac{400}{41}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{400}{41}, x = - \frac{400}{41}

\frac{400}{41} = \frac{20}{41}

- \frac{400}{41} = - \frac{20}{41}

x = \frac{20}{41}, x = - \frac{20}{41}

- 3 x^{2} - 10 x + 4 = 0

0 = x^{2} + 6 x + 11

x^{2} - 15 x - 80 = 170

5 x^{2} - 3 x + 2 = 1

2 x^{2} - 20 x + 32 = 0

What are the solutions to the equation (x^2)/(25)+(x^2)/(16)=1 ?
The solutions to the equation (x^2)/(25)+(x^2)/(16)=1 are x=(20)/(sqrt(41)),x=-(20)/(sqrt(41))
Find the zeros of (x^2)/(25)+(x^2)/(16)=1
The zeros of (x^2)/(25)+(x^2)/(16)=1 are x=(20)/(sqrt(41)),x=-(20)/(sqrt(41))