What are the solutions to the equation 5x^2-11x-2=0 ?

The solutions to the equation 5x^2-11x-2=0 are x=(11+sqrt(161))/(10),x=(11-sqrt(161))/(10)

Find the zeros of 5x^2-11x-2=0

The zeros of 5x^2-11x-2=0 are x=(11+sqrt(161))/(10),x=(11-sqrt(161))/(10)

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5 x^{2} - 11 x - 2 = 0

x = \frac{11 + 161}{10}, x = \frac{11 - 161}{10}

Decimal Notation

x = 2.36885 \dots, x = - 0.16885 \dots

Solution steps

5 x^{2} - 11 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 11)^{2} - 4 \cdot 5 (- 2) = 161

x_{1, 2} = \frac{- ( - 11 ) \pm 161}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 161}{2 \cdot 5}, x_{2} = \frac{- ( - 11 ) - 161}{2 \cdot 5}

x = \frac{- ( - 11 ) + 161}{2 \cdot 5} : \frac{11 + 161}{10}

x = \frac{- ( - 11 ) - 161}{2 \cdot 5} : \frac{11 - 161}{10}

The solutions to the quadratic equation are:

x = \frac{11 + 161}{10}, x = \frac{11 - 161}{10}

x^{2} + 4 x - 30 = 0

x^{2} + 3 x - 40 = 0

3 x^{2} + 28 = 0

2 x^{2} - 126 = 0

18 x^{2} = 12 x

What are the solutions to the equation 5x^2-11x-2=0 ?
The solutions to the equation 5x^2-11x-2=0 are x=(11+sqrt(161))/(10),x=(11-sqrt(161))/(10)
Find the zeros of 5x^2-11x-2=0
The zeros of 5x^2-11x-2=0 are x=(11+sqrt(161))/(10),x=(11-sqrt(161))/(10)