What are the solutions to the equation 9^2+b^2=10^2 ?

The solutions to the equation 9^2+b^2=10^2 are b=sqrt(19),b=-sqrt(19)

Find the zeros of 9^2+b^2=10^2

The zeros of 9^2+b^2=10^2 are b=sqrt(19),b=-sqrt(19)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9^{2} + b^{2} = 1 0^{2}

b = 19, b = - 19

Decimal Notation

b = 4.35889 \dots, b = - 4.35889 \dots

Solution steps

9^{2} + b^{2} = 1 0^{2}

Move

9^{2}

to the right side

b^{2} = 19

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 19, b = - 19

12 x^{2} - 4 x - 5 = 0

48 = x^{2} + 8 x

- 5 m^{2} = - 6 m

x^{2} - 7 x = 9

4 x^{2} = - 24 x

What are the solutions to the equation 9^2+b^2=10^2 ?
The solutions to the equation 9^2+b^2=10^2 are b=sqrt(19),b=-sqrt(19)
Find the zeros of 9^2+b^2=10^2
The zeros of 9^2+b^2=10^2 are b=sqrt(19),b=-sqrt(19)