What are the solutions to the equation 4x^2-28x+49=64 ?

The solutions to the equation 4x^2-28x+49=64 are x= 15/2 ,x=-1/2

Find the zeros of 4x^2-28x+49=64

The zeros of 4x^2-28x+49=64 are x= 15/2 ,x=-1/2

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4 x^{2} - 28 x + 49 = 64

x = \frac{15}{2}, x = - \frac{1}{2}

Decimal Notation

x = 7.5, x = - 0.5

Solution steps

4 x^{2} - 28 x + 49 = 64

Move

64

to the left side

4 x^{2} - 28 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 (- 15) = 32

x_{1, 2} = \frac{- ( - 28 ) \pm 32}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 32}{2 \cdot 4}, x_{2} = \frac{- ( - 28 ) - 32}{2 \cdot 4}

x = \frac{- ( - 28 ) + 32}{2 \cdot 4} : \frac{15}{2}

x = \frac{- ( - 28 ) - 32}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{15}{2}, x = - \frac{1}{2}

x^{2} + 6 x + 15

x^{2} + 6 x + 17

x^{2} + 6 x + 18

- 10 = 0 + 5 t + \frac{1}{2} (9.81 t^{2})

- 6 x = x^{2} + 10

What are the solutions to the equation 4x^2-28x+49=64 ?
The solutions to the equation 4x^2-28x+49=64 are x= 15/2 ,x=-1/2
Find the zeros of 4x^2-28x+49=64
The zeros of 4x^2-28x+49=64 are x= 15/2 ,x=-1/2