What are the solutions to the equation 3x^2-2x=-5 ?

The solutions to the equation 3x^2-2x=-5 are x= 1/3+i(sqrt(14))/3 ,x= 1/3-i(sqrt(14))/3

Find the zeros of 3x^2-2x=-5

The zeros of 3x^2-2x=-5 are x= 1/3+i(sqrt(14))/3 ,x= 1/3-i(sqrt(14))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 2 x = - 5

x = \frac{1}{3} + i \frac{14}{3}, x = \frac{1}{3} - i \frac{14}{3}

Solution steps

3 x^{2} - 2 x = - 5

Move

5

to the left side

3 x^{2} - 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 5 : 214 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 14 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 14 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 14 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 14 i}{2 \cdot 3} : \frac{1}{3} + i \frac{14}{3}

x = \frac{- ( - 2 ) - 2 14 i}{2 \cdot 3} : \frac{1}{3} - i \frac{14}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{14}{3}, x = \frac{1}{3} - i \frac{14}{3}

x^{2} - 10 x + 21 = 0

x^{2} - 10 x + 24 = 0

r^{2} - 6 r + 5 = 0

x, Lx - x^{2} - \frac{1}{6} L^{2} = 0

y^{2} + 3 y - 18 = 0

What are the solutions to the equation 3x^2-2x=-5 ?
The solutions to the equation 3x^2-2x=-5 are x= 1/3+i(sqrt(14))/3 ,x= 1/3-i(sqrt(14))/3
Find the zeros of 3x^2-2x=-5
The zeros of 3x^2-2x=-5 are x= 1/3+i(sqrt(14))/3 ,x= 1/3-i(sqrt(14))/3