What are the solutions to the equation 4t^2+3t+2=0 ?

The solutions to the equation 4t^2+3t+2=0 are t=-3/8+i(sqrt(23))/8 ,t=-3/8-i(sqrt(23))/8

Find the zeros of 4t^2+3t+2=0

The zeros of 4t^2+3t+2=0 are t=-3/8+i(sqrt(23))/8 ,t=-3/8-i(sqrt(23))/8

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4 t^{2} + 3 t + 2 = 0

t = - \frac{3}{8} + i \frac{23}{8}, t = - \frac{3}{8} - i \frac{23}{8}

Solution steps

4 t^{2} + 3 t + 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

Simplify

3^{2} - 4 \cdot 4 \cdot 2 : 23 i

t_{1, 2} = \frac{- 3 \pm 23 i}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- 3 + 23 i}{2 \cdot 4}, t_{2} = \frac{- 3 - 23 i}{2 \cdot 4}

t = \frac{- 3 + 23 i}{2 \cdot 4} : - \frac{3}{8} + i \frac{23}{8}

t = \frac{- 3 - 23 i}{2 \cdot 4} : - \frac{3}{8} - i \frac{23}{8}

The solutions to the quadratic equation are:

t = - \frac{3}{8} + i \frac{23}{8}, t = - \frac{3}{8} - i \frac{23}{8}

x, 7 x^{2} - 63 x y + 13 y^{2} - 16 = 0

x, x^{2} + 2 x - 2 = 0

x^{2} = x + 90

9 m^{2} + 6 m + 6 = 5

m^{2} - 7 m + 10 = 0

What are the solutions to the equation 4t^2+3t+2=0 ?
The solutions to the equation 4t^2+3t+2=0 are t=-3/8+i(sqrt(23))/8 ,t=-3/8-i(sqrt(23))/8
Find the zeros of 4t^2+3t+2=0
The zeros of 4t^2+3t+2=0 are t=-3/8+i(sqrt(23))/8 ,t=-3/8-i(sqrt(23))/8