What are the solutions to the equation q^2+9q=10 ?

The solutions to the equation q^2+9q=10 are q=1,q=-10

Find the zeros of q^2+9q=10

The zeros of q^2+9q=10 are q=1,q=-10

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q^{2} + 9 q = 10

q = 1, q = - 10

Solution steps

q^{2} + 9 q = 10

Move

10

to the left side

q^{2} + 9 q - 10 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 10) = 11

q_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 9 + 11}{2 \cdot 1}, q_{2} = \frac{- 9 - 11}{2 \cdot 1}

q = \frac{- 9 + 11}{2 \cdot 1} : 1

q = \frac{- 9 - 11}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

q = 1, q = - 10

2 x^{2} + 12 x + 19 = 0

x^{2} + 7 = 3

x^{2} = \frac{49}{64}

(3 x + 5) (2 x - 3) = - 8

50 = 2 x^{2} + 16 x + 32

What are the solutions to the equation q^2+9q=10 ?
The solutions to the equation q^2+9q=10 are q=1,q=-10
Find the zeros of q^2+9q=10
The zeros of q^2+9q=10 are q=1,q=-10