What are the solutions to the equation -2x^2+12x-14=0 ?

The solutions to the equation -2x^2+12x-14=0 are x=3-sqrt(2),x=3+sqrt(2)

Find the zeros of -2x^2+12x-14=0

The zeros of -2x^2+12x-14=0 are x=3-sqrt(2),x=3+sqrt(2)

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- 2 x^{2} + 12 x - 14 = 0

x = 3 - 2, x = 3 + 2

Decimal Notation

x = 1.58578 \dots, x = 4.41421 \dots

Solution steps

- 2 x^{2} + 12 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) ( - 14 )}{2 ( - 2 )}

1 2^{2} - 4 (- 2) (- 14) = 42

x_{1, 2} = \frac{- 12 \pm 4 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 12 + 4 2}{2 ( - 2 )}, x_{2} = \frac{- 12 - 4 2}{2 ( - 2 )}

x = \frac{- 12 + 4 2}{2 ( - 2 )} : 3 - 2

x = \frac{- 12 - 4 2}{2 ( - 2 )} : 3 + 2

The solutions to the quadratic equation are:

x = 3 - 2, x = 3 + 2

0 = - x^{2} + 2

- x^{2} = 3 x - 10

x^{2} - 8 x + 5 = 0

9 m^{2} - 36 = 0

x^{2} + x - 6 = 0

What are the solutions to the equation -2x^2+12x-14=0 ?
The solutions to the equation -2x^2+12x-14=0 are x=3-sqrt(2),x=3+sqrt(2)
Find the zeros of -2x^2+12x-14=0
The zeros of -2x^2+12x-14=0 are x=3-sqrt(2),x=3+sqrt(2)